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class ScalaUtil extends AnyRef

By default scalaIdentifier uses underscores as needed for various cases that need translation of the given identifier to make it valid Scala. Similarly, getClassName also does some related logic.

With this flag set to true, both methods will change their logic to uses backticks instead of replacing or removing the characters that would make the resulting identifiers invalid.

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Instance Constructors

  1. new ScalaUtil(useBackticks: Boolean = false)

    useBackticks

    False by default

Value Members

  1. final def !=(arg0: Any): Boolean
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  8. def finalize(): Unit
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  9. final def getClass(): Class[_]
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  10. def getClassName(symbol: String): String

    Returns a class name from the given symbol.

    Returns a class name from the given symbol. If useBackticks: This is basically capitalizing the first character that can be capitalized. If none, then a U is prepended. Otherwise: Since underscores are specially used in generated code, this method camelizes the symbol in case of any underscores.

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  13. final def ne(arg0: AnyRef): Boolean
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  14. final def notify(): Unit
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  15. final def notifyAll(): Unit
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  16. def scalaIdentifier(symbol: String): String

    Returns a valid scala identifier from the given symbol:

    Returns a valid scala identifier from the given symbol:

    - encloses the symbol in backticks if the symbol is a scala reserved word; - appends an underscore if the symbol corresponds to a no-arg method in scope; - otherwise:

    • returns symbol if it is a valid java identifier
    • otherwise: if useBackticks is true, encloses symbol in backticks otherwise, returns javaGenerator.javaIdentifier(symbol)
  17. final def synchronized[T0](arg0: ⇒ T0): T0
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  21. final def wait(arg0: Long): Unit
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