object Maps
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final
def
!=(arg0: Any): Boolean
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final
def
##(): Int
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final
def
==(arg0: Any): Boolean
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final
def
asInstanceOf[T0]: T0
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def
clone(): AnyRef
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def
deepAsJava[K](src: Map[K, AnyRef]): Map[K, AnyRef]
Given a scala.collection.immutable.Map[k, AnyRef], this method will return a java.util.Map[k, AnyRef] where each value has been transformed such that:
Given a scala.collection.immutable.Map[k, AnyRef], this method will return a java.util.Map[k, AnyRef] where each value has been transformed such that:
- if the value is also a scala map, then it will be recursively converted into a java map
- otherwise it will be returned as is
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def
deepAsScala[K](src: Map[K, AnyRef]): Map[K, AnyRef]
Given a java.util.Map[k, AnyRef], this method will return a scala.collection.immutable.Map[k, AnyRef] where each value has been transformed such that:
Given a java.util.Map[k, AnyRef], this method will return a scala.collection.immutable.Map[k, AnyRef] where each value has been transformed such that:
- if the value is also a java map, then it will be recursively converted into a scala map
- otherwise it will be returned as is
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final
def
eq(arg0: AnyRef): Boolean
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def
equals(arg0: Any): Boolean
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def
finalize(): Unit
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- @throws( classOf[java.lang.Throwable] )
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def
flatten[V](map: Map[String, V], separator: String = "."): Map[String, V]
Given a nested map of strings, will create a flatted map, where the strings are joined with a separator.
Given a nested map of strings, will create a flatted map, where the strings are joined with a separator. So given Map("a" -> "b", "c" -> Map("d" -> "e")) then the output will be Map("a" -> "b", "c.d" -> "e")
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final
def
getClass(): Class[_]
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def
hashCode(): Int
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final
def
isInstanceOf[T0]: Boolean
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final
def
ne(arg0: AnyRef): Boolean
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final
def
notify(): Unit
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final
def
notifyAll(): Unit
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final
def
synchronized[T0](arg0: ⇒ T0): T0
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def
toString(): String
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final
def
wait(): Unit
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final
def
wait(arg0: Long, arg1: Int): Unit
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final
def
wait(arg0: Long): Unit
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