- 所有超级接口:
Cloneable,LongIterator
Simple extension to the IntIterator interface.
It allows you to "skip" values using the advanceIfNeeded
method, and to look at the value without advancing (peekNext).
This richer interface enables efficient algorithms over
iterators of longs.
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方法概要
修饰符和类型方法说明voidadvanceIfNeeded(long thresholdVal) If needed, for a forwards iterator advance as long as the next value is smaller than thresholdVal For a reverse iterator advance as long as the next value is greater than thresholdVal The advanceIfNeeded method is used for performance reasons, to skip over unnecessary repeated calls to next.clone()Creates a copy of the iterator.longpeekNext()Look at the next value without advancing The peek is useful when working with several iterators at once.从接口继承的方法 org.bitlap.roaringbitmap.longlong.LongIterator
hasNext, next
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方法详细资料
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advanceIfNeeded
void advanceIfNeeded(long thresholdVal) If needed, for a forwards iterator advance as long as the next value is smaller than thresholdVal For a reverse iterator advance as long as the next value is greater than thresholdVal The advanceIfNeeded method is used for performance reasons, to skip over unnecessary repeated calls to next. Suppose for example that you wish to compute the intersection between an ordered list of longs (e.g., longs[] x = {1,4,5}) and a PeekableIntIterator. You might do it as follows...
The benefit of calling advanceIfNeeded is that each such call can be much faster than repeated calls to "next". The underlying implementation can "skip" over some data.PeekableLongIterator j = // get an iterator long val = // first value from my other data structure j.advanceIfNeeded(val); while ( j.hasNext() ) { if(j.next() == val) { // ah! ah! val is in the intersection... // do something here val = // get next value? } j.advanceIfNeeded(val); }- 参数:
thresholdVal- threshold
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peekNext
long peekNext()Look at the next value without advancing The peek is useful when working with several iterators at once. Suppose that you have 100 iterators, and you want to compute their intersections without materializing the result. You might do it as follows...
Notice how the peek method allows you to compare iterators in a way that the next method could not do.PriorityQueue pq = new PriorityQueue(100, new Comparator<PeekableIntIterator>() { public int compare(PeekableIntIterator a, PeekableIntIterator b) { return a.peek() - b.peek(); } }); //... populate pq while(! pq.isEmpty() ) { // get iterator with a smallest value PeekableLongIterator pi = pq.poll(); long x = pi.next(); // advance // do something with x if(pi.hasNext()) pq.add(pi) }- 返回:
- next value
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clone
PeekableLongIterator clone()Creates a copy of the iterator.- 指定者:
clone在接口中LongIterator- 返回:
- a clone of the current iterator
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